问题描述
<p ng-repeat='links in slides'> <p ng-repeat='link in links'>{{link.name}}</p></p>
slides是一个二维数组，我以上的代码会报错Error: [ngRepeat:dupes]
$http.get(’index.php?option=com_mtree&task=ajax.load’).success(function(response) { if(response.status) {$scope.links = response.links;if(typeof response.links != ’undefined’) { var slides = [], slide; for(var i=0; i<response.links.length;) {slide = [];for(var c=0; c<3&&c<response.links.length; c++, i++) { slide.push(response.links.indexOf(i));}slides.push(slide); } $scope.slides = slides;}/*setTimeout(function(){ jQuery(’.saved-list .slideshow’).cycle(’destroy’); jQuery(’.saved-list .slideshow’).cycle();}, 0);*/ }});
请问如何实现嵌套？
问题解答
回答1：直接的答案：
<p ng-repeat='links in slides'> <p ng-repeat='link in links track by $index'>{{link.name}}</p></p>
Error: [ngRepeat:dupes]这个出错提示具体到题主的情况，意思是指数组中有2个以上的相同数字。ngRepeat不允许collection中存在两个相同Id的对象
For example: item in items is equivalent to item in items track by $id(item). This implies that the DOM elements will be associated by item identity in the array.
对于数字对象来说，它的id就是它自身的值，因此，数组中是不允许存在两个相同的数字的。为了规避这个错误，需要定义自己的track by表达式。例如：item in items track by item.id或者item in items track by fnCustomId(item)。嫌麻烦的话，直接拿循环的索引变量$index来用item in items track by $index
fiddle示例：http://jsfiddle.net/shiedman/PLV6G/
回答2：http://jsfiddle.net/Nelson_Pan/bcPxe/1
