问题描述
刚接触ionic和angular：.factory(’Recos’, function() {
var recos=[ { recoid:0,cityname:'上海',cityintroduce:'',citytext:'',img:'', }, {recoid:1,cityname:'北京',cityintroduce:'',citytext:'',img:'', }, {recoid:2,cityname:'深圳',cityintroduce:'',citytext:'',img:'', }, {recoid:3,cityname:'',cityintroduce:'',citytext:'”。',img:'', }];return {allreco: function() {return recos; //标注},get: function(recoid) { for (var i = 0; i < recos.length; i++) { if (recos[i].recoid === parseInt(recoid)) { return recos[i]; } };},
};})
'//标注'的地方这样是正常的，但是改成return recos[0]或者recos[1]...前台调用就不显示数据，这是为什么呢~;因为想做一个简单的匹配功能：
return {
allreco: function() { var city = localStorage.city; for (var i = 0; i < recos.length; i++) { if (city.indexOf(recos[i].cityname) != -1){return recos[i]; } };},get: function(recoid) { for (var i = 0; i < recos.length; i++) { if (recos[i].recoid === parseInt(recoid)) { return recos[i]; } };},
};
碰到了这个问题,不知道其中原因。
问题解答
回答1：allreco的意思应该是返回所有的reco，为什么会变成return recos[i]，你是想返回所有在localStorage.city里面的reco吗？
allreco: function(){ var city = localStorage.city; var result=[] for (var i = 0; i < recos.length; i++) { if (city.indexOf(recos[i].cityname) != -1){ result.push(recos[i]); } }; return result;}
